Circular turns of radius r in a race track are often banked at an angle θ to allow the cars to achieve higher speeds around the turns. Assume friction is not present, and use the coordinate system specified.
Now assume that the car is moving at 17 m/s and the radius of the track is 410 m. What is the angle θ in degrees?
use tan(theta)= (v^2)/r*g
so solve (17m/s ^2 )/ (410m*9.8m/s^2)
tan^-1 (.0719)
the angle should be 4.11 degrees.
Hello Sarah. How did you find this equation with tangent?
ReplyDeleteThanks!